2644y^2-232y+5=0

Solution for 2644y^2-232y+5=0 equation:

2644y^2-232y+5=0

a = 2644; b = -232; c = +5;
Δ = b2-4ac
Δ = -2322-4·2644·5
Δ = 944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{944}=\sqrt{16*59}=\sqrt{16}*\sqrt{59}=4\sqrt{59}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-232)-4\sqrt{59}}{2*2644}=\frac{232-4\sqrt{59}}{5288}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-232)+4\sqrt{59}}{2*2644}=\frac{232+4\sqrt{59}}{5288}
$